play phryzby with physics

Dropped From a Speeding Train

solved NewtonsSecondLaw

Q. A stone of mass 0.1 kgms=0.1kg is dropped from the window of a train accelerating with 1 m/s²|at(s)|=1m/s². Neglect air resistanceFsa(f)=0N, and take g asWs=−|Ws| 10 m/s²g=10m/s². What is the magnitude of the net force acting on the stone just after it is dropped, in newtons?

stoneaweight
Inputs
ms
0.1 kg
|at|
1 m/s²
g
10 m/s²
Outputs
force|Fnet,s|?

How it's solved

Solved with NewtonsSecondLaw

Given

  • ms=0.1kg
  • |at(s)|=1m/s²
  • g=10m/s²
  • Fsa(f)=0N from “Neglect air resistance”
  • Ws=−|Ws| from “take g as”

Find |Fnet,s(f)|.

Working
  1. weight of a body(stone)|Ws|=ms⋅g
  2. |Ws|=0.1⋅10
  3. |Ws|=1N
  4. take g asWs=−|Ws|
  5. Ws=−1
  6. Ws=−1N
  7. net force is the resultant(stone, falling, y)Fnet,s(f)=Fsa(f)+Ws
  8. Fnet,s(f)=0+(−1)
  9. Fnet,s(f)=−1N
  10. magnitude from components(net force on stone during falling)|Fnet,s(f)|=Fnet,s(f)2
  11. |Fnet,s(f)|=(−1)2
  12. |Fnet,s(f)|=1N
Conclusion

Once the stone leaves the window the train no longer pushes it, so the only force left is its weight; how the train is moving makes no difference.

The web of concepts

given read from the words equation asked

The Ruby that solves it

The question and its solution are small Ruby files. The engine runs them.

question.rb
1require_relative "../physics"23question :dropped_from_a_speeding_train do4  kind :numerical5  describes "A stone of mass %{mass} is dropped from the window of a train accelerating with %{train_acceleration}. " \6            "Neglect air resistance, and take g as %{gravity}. %{force} just after it is dropped, in newtons?"7  given mass: "0.1 kg"8  given train_acceleration: "1 m/s2"9  given gravity: "10 m/s2"10  asks force: "What is the magnitude of the net force acting on the stone"11end
solution.rb
1require_relative "../questions/dropped_from_a_speeding_train"2require_relative "../science/laws_of_motion/newtons_second_law"34solve :dropped_from_a_speeding_train, using: NewtonsSecondLaw do5  objects :stone, :train, :air6  axes :y7  train.goes(:speeding_up)8  stone.goes(:falling)9  deduce_from "take g as", stone.weight.direction => -y1011  take mass: stone.mass12  take train_acceleration: train.acceleration.magnitude13  take gravity: g1415  deduce_from "Neglect air resistance", stone.force(by: air) => "0 N"1617  force = stone.net_force.magnitude18  answer force:, in: "N"1920  conclusion "Once the stone leaves the window the train no longer pushes it, so the only force left is its " \21             "weight; how the train is moving makes no difference."22end
playground.rb
1require_relative "../solutions/dropped_from_a_speeding_train"23play_with :dropped_from_a_speeding_train do4  title "Dropped From a Speeding Train"5end
The laws it drew on
quantitywrittenunitswithinfrom
volumevolume——Vectors
massmkg0 … ∞Vectors
speedspeed——Vectors
densitydensity——Vectors
number of molesn——Vectors
angular frequencyangularfrequency——Vectors
workwork——Vectors
currentcurrent——Vectors
temperaturetemperature——Vectors
pressurepressure——Vectors
timets0 … 1e+05Vectors
powerpower——Vectors
total path lengths——Vectors
energyenergy——Vectors
gravitational potentialgravitationalpotential——Vectors
coefficient of frictionμ——Vectors
chargecharge——Vectors
accelerationam/s²—Vectors
velocityvm/s—Vectors
displacementΔxm—Vectors
angular velocityangularvelocity——Vectors
forceFN—Vectors
angular momentumangularmomentum——Vectors
linear momentumplin——Vectors
electric fieldelectricfield——Vectors
average velocityvavm/s—Vectors
magnetic momentmagneticmoment——Vectors
relative velocityvAB——Vectors
impulseimpulse——Vectors
first vectorA—0 … ∞Vectors
second vectorB—0 … ∞Vectors
angle betweenφ—0 … 3.142Vectors
resultantR—0 … ∞Vectors
resultant directionβ—0 … 3.142Vectors
directionα—-3.142 … 3.142Vectors
x componentAx——Vectors
y componentAy——Vectors
positionxm—Velocity
path lengthdm—Velocity
time takenΔts0 … 1e+05Velocity
average speedcavm/s—Velocity
starting positionx0m—Velocity
final positionxm—Velocity
change of velocityΔvm/s—Acceleration
average accelerationaavm/s²—Acceleration
starting velocityv0m/s—Acceleration
final velocityvm/s—Acceleration
gravitygm/s²—UniformAcceleration
net forceFnetN—NewtonsSecondLaw
weightWN—NewtonsSecondLaw
displacement of train during speeding up along yΔxt(s)m—
position of train at end of speeding up along yxt(s₁)m—
position of train at start of speeding up along yxt(s₀)m—
displacement of stone during falling along yΔxs(f)m—
position of stone at end of falling along yxs(f₁)m—
position of stone at start of falling along yxs(f₀)m—
average velocity of train during speeding up along yvav,t(s)m/s—
time taken of speeding upΔtss0 … 1e+05
average velocity of stone during falling along yvav,s(f)m/s—
time taken of fallingΔtfs0 … 1e+05
average speed of train during speeding upcav,t(s)m/s—
path length of train during speeding updt(s)m—
average speed of stone during fallingcav,s(f)m/s—
path length of stone during fallingds(f)m—
change of velocity of train during speeding up along yΔvt(s)m/s—
velocity of train at end of speeding up from ground along yvt(s₁)m/s—
velocity of train at start of speeding up from ground along yvt(s₀)m/s—
change of velocity of stone during falling along yΔvs(f)m/s—
velocity of stone at end of falling from ground along yvs(f₁)m/s—
velocity of stone at start of falling from ground along yvs(f₀)m/s—
average acceleration of train during speeding up along yaav,t(s)m/s²—
average acceleration of stone during falling along yaav,s(f)m/s²—
acceleration of train during speeding up along yat(s)m/s²—
acceleration of stone during falling along yas(f)m/s²—
net force on train during speeding up along yFnet,t(s)N—
mass of trainmtkg0 … ∞
net force on stone during falling along yFnet,s(f)N—
mass of stonemskg0 … ∞
mass of airmakg0 … ∞
weight on ground|Wg|N—
weight on stone|Ws|N—
weight on train|Wt|N—
weight on air|Wa|N—
force on stone by air during falling|Fsa(f)|N—
weight on stone along yWsN—
force on stone by air during falling along yFsa(f)N—
displacement of train during speeding up|Δxt(s)|m—
position of train at end of speeding up|xt(s₁)|m—
position of train at start of speeding up|xt(s₀)|m—
displacement of stone during falling|Δxs(f)|m—
position of stone at end of falling|xs(f₁)|m—
position of stone at start of falling|xs(f₀)|m—
average velocity of train during speeding up|vav,t(s)|m/s—
average velocity of stone during falling|vav,s(f)|m/s—
change of velocity of train during speeding up|Δvt(s)|m/s—
velocity of train at end of speeding up from ground|vt(s₁)|m/s—
velocity of train at start of speeding up from ground|vt(s₀)|m/s—
change of velocity of stone during falling|Δvs(f)|m/s—
velocity of stone at end of falling from ground|vs(f₁)|m/s—
velocity of stone at start of falling from ground|vs(f₀)|m/s—
average acceleration of train during speeding up|aav,t(s)|m/s²—
average acceleration of stone during falling|aav,s(f)|m/s²—
acceleration of train during speeding up|at(s)|m/s²—
acceleration of stone during falling|as(f)|m/s²—
net force on train during speeding up|Fnet,t(s)|N—
net force on stone during falling|Fnet,s(f)|N—
x0≡xi(start of motion)
starting position
x≡xi(end of motion)
final position
v0≡vi(start of motion)
starting velocity
v≡vi(end of motion)
final velocity
t≡Δtm
time
A=Ax2+Ay2
magnitude from components
di(whole)=di(part 1)+di(part 2)
path in parts
Δtw=Δtp+Δtp
time in parts
ai(part 1)=ai(whole)
steady through its parts
mb≠0
has mass?
R2=A2+B2+2⋅A⋅B⋅cos⁡φ
law of cosines
R⋅sin⁡β=B⋅sin⁡φ
law of sines
R⋅cos⁡β=A+B⋅cos⁡φ
along the first
Ax=A⋅cos⁡α
resolved along x
Ay=A⋅sin⁡α
resolved along y
Δxt(s)=xt(s₁)-xt(s₀)
change of position(speeding up, y)
Δxs(f)=xs(f₁)-xs(f₀)
change of position(falling, y)
vav,t(s)=Δxt(s)Δts
displacement a time(speeding up, y)
vav,s(f)=Δxs(f)Δtf
displacement a time(falling, y)
cav,t(s)=dt(s)Δts
path a time(speeding up, y)
cav,s(f)=ds(f)Δtf
path a time(falling, y)
Δvt(s)=vt(s₁)-vt(s₀)
velocity gained(speeding up, y)
Δvs(f)=vs(f₁)-vs(f₀)
velocity gained(falling, y)
aav,t(s)=Δvt(s)Δts
velocity gained a time(speeding up, y)
aav,s(f)=Δvs(f)Δtf
velocity gained a time(falling, y)
vt(s₁)=vt(s₀)+at(s)⋅Δts
velocity after a time(speeding up, y)
vs(f₁)=vs(f₀)+as(f)⋅Δtf
velocity after a time(falling, y)
xt(s₁)=xt(s₀)+vt(s₀)⋅Δts+at(s)⋅Δts22
position after a time(speeding up, y)
xs(f₁)=xs(f₀)+vs(f₀)⋅Δtf+as(f)⋅Δtf22
position after a time(falling, y)
vt(s₁)2=vt(s₀)2+2⋅at(s)⋅(xt(s₁)-xt(s₀))
velocity after a distance(speeding up, y)
vs(f₁)2=vs(f₀)2+2⋅as(f)⋅(xs(f₁)-xs(f₀))
velocity after a distance(falling, y)
xt(s₁)-xt(s₀)=(vt(s₁)+vt(s₀))⋅Δts2
mean of the velocities(speeding up, y)
xs(f₁)-xs(f₀)=(vs(f₁)+vs(f₀))⋅Δtf2
mean of the velocities(falling, y)
Fnet,t(s)=mt⋅at(s)
second law(speeding up, y)
Fnet,s(f)=ms⋅as(f)
second law(falling, y)
|Ws|=ms⋅g
weight of a body(stone)
Fnet,s(f)=Fsa(f)+Ws
net force is the resultant(stone, falling, y)
|Δxt(s)|=Δxt(s)2
magnitude from components(displacement of train during speeding up)
|xt(s₁)|=xt(s₁)2
magnitude from components(position of train at end of speeding up)
|xt(s₀)|=xt(s₀)2
magnitude from components(position of train at start of speeding up)
|Δxs(f)|=Δxs(f)2
magnitude from components(displacement of stone during falling)
|xs(f₁)|=xs(f₁)2
magnitude from components(position of stone at end of falling)
|xs(f₀)|=xs(f₀)2
magnitude from components(position of stone at start of falling)
|vav,t(s)|=vav,t(s)2
magnitude from components(average velocity of train during speeding up)
|vav,s(f)|=vav,s(f)2
magnitude from components(average velocity of stone during falling)
|Δvt(s)|=Δvt(s)2
magnitude from components(change of velocity of train during speeding up)
|vt(s₁)|=vt(s₁)2
magnitude from components(velocity of train at end of speeding up from ground)
|vt(s₀)|=vt(s₀)2
magnitude from components(velocity of train at start of speeding up from ground)
|Δvs(f)|=Δvs(f)2
magnitude from components(change of velocity of stone during falling)
|vs(f₁)|=vs(f₁)2
magnitude from components(velocity of stone at end of falling from ground)
|vs(f₀)|=vs(f₀)2
magnitude from components(velocity of stone at start of falling from ground)
|aav,t(s)|=aav,t(s)2
magnitude from components(average acceleration of train during speeding up)
|aav,s(f)|=aav,s(f)2
magnitude from components(average acceleration of stone during falling)
|at(s)|=at(s)2
magnitude from components(acceleration of train during speeding up)
|as(f)|=as(f)2
magnitude from components(acceleration of stone during falling)
|Fnet,t(s)|=Fnet,t(s)2
magnitude from components(net force on train during speeding up)
|Fnet,s(f)|=Fnet,s(f)2
magnitude from components(net force on stone during falling)
|Ws|=Ws2
magnitude from components(weight on stone)
|Fsa(f)|=Fsa(f)2
magnitude from components(force on stone by air during falling)
Ws=−|Ws|
take g as
ms≠0
has mass?(stone)
mt≠0
has mass?(train)
ma≠0
has mass?(air)
Fnet,s(f)=0
free of forces?(stone, falling)
Fnet,t(s)=0
free of forces?(train, speeding up)