An Object at 140 °F

Q. If temperature of an object is 140 °F, then its temperature in centigrade is expects D

What the draft establishes

Fills in once a draft is checked.

The web of concepts

given read from the words equation asked

The equations it used

None yet.

Check an answer

Q. If temperature of an object is 140 °F $T = 140$ °F, then its temperature in centigrade is

The playground

The solution

Solved with Units

Given

$T = 140$ °F

Find $T$ .

Working

$T = 140$ °F $= 333.15$ K
$T = 333.15$ K $= 60$ °C

Conclusion

A Fahrenheit degree is five ninths of a Celsius one and the ice point is 32 °F, so 140 °F is 108 Fahrenheit degrees above it, which is 60 °C.

The Ruby

1require_relative "../physics"23question :an_object_at_one_hundred_forty_fahrenheit do4  kind :scq5  describes "If temperature of an object is %{hot}, then its temperature in centigrade is"6  given hot: "140 °F"78  option "105 °C"9  option "32 °C"10  option "140 °C"11  option "60 °C"12end

1require_relative "../questions/an_object_at_one_hundred_forty_fahrenheit"2require_relative "../science/units_and_measurement/units"34solve :an_object_at_one_hundred_forty_fahrenheit, using: Units do5  take hot: :T6  answer find_value(:T, in: "°C")78  conclusion "A Fahrenheit degree is five ninths of a Celsius one and the ice point is 32 °F, so 140 °F is " \9             "108 Fahrenheit degrees above it, which is 60 °C."10end

1require_relative "../solutions/an_object_at_one_hundred_forty_fahrenheit"23play_with :an_object_at_one_hundred_forty_fahrenheit do4  title "An Object at 140 °F"5end

The laws

quantity	written	units	within	from
speed of light	$c$	m/s	—	Units
avogadro constant	$N_{A}$	mol⁻¹	—	Units
length	$l$	m	0 … ∞	Units
mass	$m$	kg	—	Units
time	$t$	s	0 … ∞	Units
electric current	$I$	A	—	Units
temperature	$T$	K	—	Units
amount of substance	$n$	mol	—	Units
luminous intensity	$I_{v}$	cd	—	Units
arc length	$s$	m	—	Units
radius	$r$	m	0 … ∞	Units
plane angle	$θ$	—	—	Units
area	$A$	m²	—	Units
solid angle	$Ω$	—	—	Units
light time	$t_{light}$	s	—	Units
light distance	$d_{light}$	m	—	Units
number of entities	$N$	—	—	Units
baseline	$B$	m	—	Units
distance away	$D$	m	—	Units
parallax angle	$θ_{p}$	—	—	Units

θ = \frac{s}{r}

arc over radius

Ω = \frac{A}{r^{2}}

area over radius squared

d_{light} = c \cdot t_{light}

distance at light speed

N = n \cdot N_{A}

entities in moles

θ_{p} = \frac{B}{D}

baseline over distance