An Object at 140 °F

solved Units

Q. If temperature of an object is 140 °F $T = 140$ °F, then its temperature in centigrade is

How it's solved

Solved with Units

Given

$T = 140$ °F

Find $T$ .

Working

$T = 140$ °F $= 333.15$ K
$T = 333.15$ K $= 60$ °C

Conclusion

A Fahrenheit degree is five ninths of a Celsius one and the ice point is 32 °F, so 140 °F is 108 Fahrenheit degrees above it, which is 60 °C.

The web of concepts

given read from the words equation asked

The Ruby that solves it

The question and its solution are small Ruby files. The engine runs them.

question.rb

1require_relative "../physics"23question :an_object_at_one_hundred_forty_fahrenheit do4  kind :scq5  describes "If temperature of an object is %{hot}, then its temperature in centigrade is"6  given hot: "140 °F"78  option "105 °C"9  option "32 °C"10  option "140 °C"11  option "60 °C"12end

solution.rb

1require_relative "../questions/an_object_at_one_hundred_forty_fahrenheit"2require_relative "../science/units_and_measurement/units"34solve :an_object_at_one_hundred_forty_fahrenheit, using: Units do5  take hot: :T6  answer find_value(:T, in: "°C")78  conclusion "A Fahrenheit degree is five ninths of a Celsius one and the ice point is 32 °F, so 140 °F is " \9             "108 Fahrenheit degrees above it, which is 60 °C."10end

playground.rb

1require_relative "../solutions/an_object_at_one_hundred_forty_fahrenheit"23play_with :an_object_at_one_hundred_forty_fahrenheit do4  title "An Object at 140 °F"5end

The laws it drew on

quantity	written	units	within	from
speed of light	$c$	m/s	—	Units
avogadro constant	$N_{A}$	mol⁻¹	—	Units
length	$l$	m	0 … ∞	Units
mass	$m$	kg	—	Units
time	$t$	s	0 … ∞	Units
electric current	$I$	A	—	Units
temperature	$T$	K	—	Units
amount of substance	$n$	mol	—	Units
luminous intensity	$I_{v}$	cd	—	Units
arc length	$s$	m	—	Units
radius	$r$	m	0 … ∞	Units
plane angle	$θ$	—	—	Units
area	$A$	m²	—	Units
solid angle	$Ω$	—	—	Units
light time	$t_{light}$	s	—	Units
light distance	$d_{light}$	m	—	Units
number of entities	$N$	—	—	Units
baseline	$B$	m	—	Units
distance away	$D$	m	—	Units
parallax angle	$θ_{p}$	—	—	Units

θ = \frac{s}{r}

arc over radius

Ω = \frac{A}{r^{2}}

area over radius squared

d_{light} = c \cdot t_{light}

distance at light speed

N = n \cdot N_{A}

entities in moles

θ_{p} = \frac{B}{D}

baseline over distance