play phryzby with physics

A Lift Speeding Down

solved NewtonsSecondLaw

Q. A man of mass 70 kgm=70kg stands on a weighing scaleFs=|Fs| in a lift which is moving downwardsa=−|a| with a uniform acceleration of 5 m/s²|a|=5m/s². Taking g asW=−|W| 10 m/s²g=10m/s², what would be the reading on the scale, in newtons?

mana = 5 m/s²weightscale ?
Inputs
m
70 kg
|a|
5 m/s²
g
10 m/s²
Outputs
reading|Fs|?

How it's solved

Solved with NewtonsSecondLaw

Given

  • m=70kg
  • |a|=5m/s²
  • g=10m/s²
  • W=−|W| from “Taking g as”
  • a=−|a| from “downwards”
  • Fs=|Fs| from “stands on a weighing scale”

Find |Fs|.

Working
  1. downwardsa=−|a|
  2. a=−5
  3. a=−5m/s²
  4. second law(riding, y)Fnet=m⋅a
  5. Fnet=70⋅(−5)
  6. Fnet=−350N
  7. weight of a body(man)|W|=m⋅g
  8. |W|=70⋅10
  9. |W|=700N
  10. Taking g asW=−|W|
  11. W=−700
  12. W=−700N
  13. net force is the resultant(man, riding, y)Fnet=Fs+W
  14. (−350)=Fs+(−700)
  15. Fs=350N
  16. magnitude from components(force on man by scale during riding)|Fs|=Fs2
  17. |Fs|=3502
  18. |Fs|=350N
Conclusion

Speeding up downward, the man needs less than his weight held up, so the scale pushes less and reads less.

The web of concepts

given read from the words equation asked

The Ruby that solves it

The question and its solution are small Ruby files. The engine runs them.

question.rb
1require_relative "../physics"23question :a_lift_speeding_down do4  kind :numerical5  describes "A man of mass %{mass} stands on a weighing scale in a lift which is moving downwards with a uniform " \6            "acceleration of %{acceleration}. Taking g as %{gravity}, %{reading}, in newtons?"7  given mass: "70 kg"8  given acceleration: "5 m/s2"9  given gravity: "10 m/s2"10  asks reading: "what would be the reading on the scale"11end
solution.rb
1require_relative "../questions/a_lift_speeding_down"2require_relative "../science/laws_of_motion/newtons_second_law"34solve :a_lift_speeding_down, using: NewtonsSecondLaw do5  objects :man, :scale6  axes :y7  man.goes(:riding)8  deduce_from "Taking g as", man.weight.direction => -y910  take mass: man.mass11  take acceleration: man.acceleration.magnitude12  take gravity: g1314  deduce_from "downwards", man.acceleration.direction => -y15  deduce_from "stands on a weighing scale", man.force(by: scale).direction => y1617  reading = man.force(by: scale).magnitude18  answer reading:, in: "N"1920  conclusion "Speeding up downward, the man needs less than his weight held up, so the scale pushes less and " \21             "reads less."22end
playground.rb
1require_relative "../solutions/a_lift_speeding_down"23play_with :a_lift_speeding_down do4  title "A Lift Speeding Down"5end
The laws it drew on
quantitywrittenunitswithinfrom
volumevolume——Vectors
massmkg0 … ∞Vectors
speedspeed——Vectors
densitydensity——Vectors
number of molesn——Vectors
angular frequencyangularfrequency——Vectors
workwork——Vectors
currentcurrent——Vectors
temperaturetemperature——Vectors
pressurepressure——Vectors
timets0 … 1e+05Vectors
powerpower——Vectors
total path lengths——Vectors
energyenergy——Vectors
gravitational potentialgravitationalpotential——Vectors
coefficient of frictionμ——Vectors
chargecharge——Vectors
accelerationam/s²—Vectors
velocityvm/s—Vectors
displacementΔxm—Vectors
angular velocityangularvelocity——Vectors
forceFN—Vectors
angular momentumangularmomentum——Vectors
linear momentumplin——Vectors
electric fieldelectricfield——Vectors
average velocityvavm/s—Vectors
magnetic momentmagneticmoment——Vectors
relative velocityvAB——Vectors
impulseimpulse——Vectors
first vectorA—0 … ∞Vectors
second vectorB—0 … ∞Vectors
angle betweenφ—0 … 3.142Vectors
resultantR—0 … ∞Vectors
resultant directionβ—0 … 3.142Vectors
directionα—-3.142 … 3.142Vectors
x componentAx——Vectors
y componentAy——Vectors
positionxm—Velocity
path lengthdm—Velocity
time takenΔts0 … 1e+05Velocity
average speedcavm/s—Velocity
starting positionx0m—Velocity
final positionxm—Velocity
change of velocityΔvm/s—Acceleration
average accelerationaavm/s²—Acceleration
starting velocityv0m/s—Acceleration
final velocityvm/s—Acceleration
gravitygm/s²—UniformAcceleration
net forceFnetN—NewtonsSecondLaw
weightWN—NewtonsSecondLaw
displacement of man during riding along yΔxm—
position of man at end of riding along yx1m—
position of man at start of riding along yx0m—
average velocity of man during riding along yvavm/s—
time taken of ridingΔts0 … 1e+05
average speed of man during ridingcavm/s—
path length of man during ridingdm—
change of velocity of man during riding along yΔvm/s—
velocity of man at end of riding from ground along yv1m/s—
velocity of man at start of riding from ground along yv0m/s—
average acceleration of man during riding along yaavm/s²—
acceleration of man during riding along yam/s²—
net force on man during riding along yFnetN—
mass of manmkg0 … ∞
mass of scalemskg0 … ∞
weight on ground|Wg|N—
weight on man|W|N—
weight on scale|Ws|N—
force on man by scale during riding|Fs|N—
weight on man along yWN—
force on man by scale during riding along yFsN—
displacement of man during riding|Δx|m—
position of man at end of riding|x1|m—
position of man at start of riding|x0|m—
average velocity of man during riding|vav|m/s—
change of velocity of man during riding|Δv|m/s—
velocity of man at end of riding from ground|v1|m/s—
velocity of man at start of riding from ground|v0|m/s—
average acceleration of man during riding|aav|m/s²—
acceleration of man during riding|a|m/s²—
net force on man during riding|Fnet|N—
x0≡xi(start of motion)
starting position
x≡xi(end of motion)
final position
v0≡vi(start of motion)
starting velocity
v≡vi(end of motion)
final velocity
t≡Δtm
time
A=Ax2+Ay2
magnitude from components
di(whole)=di(part 1)+di(part 2)
path in parts
Δtw=Δtp+Δtp
time in parts
ai(part 1)=ai(whole)
steady through its parts
mb≠0
has mass?
R2=A2+B2+2⋅A⋅B⋅cos⁡φ
law of cosines
R⋅sin⁡β=B⋅sin⁡φ
law of sines
R⋅cos⁡β=A+B⋅cos⁡φ
along the first
Ax=A⋅cos⁡α
resolved along x
Ay=A⋅sin⁡α
resolved along y
Δx=x1-x0
change of position(riding, y)
vav=ΔxΔt
displacement a time(riding, y)
cav=dΔt
path a time(riding, y)
Δv=v1-v0
velocity gained(riding, y)
aav=ΔvΔt
velocity gained a time(riding, y)
v1=v0+a⋅Δt
velocity after a time(riding, y)
x1=x0+v0⋅Δt+a⋅Δt22
position after a time(riding, y)
v12=v02+2⋅a⋅(x1-x0)
velocity after a distance(riding, y)
x1-x0=(v1+v0)⋅Δt2
mean of the velocities(riding, y)
Fnet=m⋅a
second law(riding, y)
|W|=m⋅g
weight of a body(man)
Fnet=Fs+W
net force is the resultant(man, riding, y)
|Δx|=Δx2
magnitude from components(displacement of man during riding)
|x1|=x12
magnitude from components(position of man at end of riding)
|x0|=x02
magnitude from components(position of man at start of riding)
|vav|=vav2
magnitude from components(average velocity of man during riding)
|Δv|=Δv2
magnitude from components(change of velocity of man during riding)
|v1|=v12
magnitude from components(velocity of man at end of riding from ground)
|v0|=v02
magnitude from components(velocity of man at start of riding from ground)
|aav|=aav2
magnitude from components(average acceleration of man during riding)
|a|=a2
magnitude from components(acceleration of man during riding)
|Fnet|=Fnet2
magnitude from components(net force on man during riding)
|W|=W2
magnitude from components(weight on man)
|Fs|=Fs2
magnitude from components(force on man by scale during riding)
W=−|W|
Taking g as
a=−|a|
downwards
Fs=|Fs|
stands on a weighing scale
m≠0
has mass?(man)
ms≠0
has mass?(scale)
Fnet=0
free of forces?(man, riding)