play phryzby with physics

Part of eval main bdd945f six, agent version bdd945f

Q. A copper block of mass 2.5 kg is heated in a furnace to a temperature of 500 °C and then placed on a large ice block. Specific heat of copper = 0.39 J g⁻¹ K⁻¹; heat of fusion of water = 335 J g⁻¹. What is the maximum amount of ice that can melt, in kg? expects 1.5 kg

24 checks, 0 agreed

draft 24: failed in solution.rb, line 12 — ArgumentError: copper_block_on_ice gives the specific heat capacity of copper twice: 0.39 J g-1 K-1 and 0.39e3 J kg-1 K-1

Latest draft

question.rb1 question :copper_block_on_ice do2   kind :numerical3   describes "A copper block of %{copper_mass} is heated in a furnace to a temperature of %{hot} and then placed on a large ice block. Specific heat of copper = %{copper_heat}; heat of fusion of water = %{fusion}. %{ice_melted}, in kg?"4   given copper_mass: "2.5 kg"5   given hot: "500 °C"6   given copper_heat: "0.39 J g-1 K-1"7   given fusion: "335 J g-1"8   asks ice_melted: "What is the maximum amount of ice that can melt"9 end
solution.rb1 solve :copper_block_on_ice, using: Calorimetry do2   objects :copper, :ice3 4   take copper_mass: copper.mass5   take hot: copper.temperature_at_first6   take copper_heat: copper.specific_heat_capacity7   take fusion: ice.latent_heat8 9   deduce_from "placed on a large ice block", ice.temperature_at_first => "0 °C"10   deduce_from "maximum amount of ice that can melt", copper.heat_to_warm => -(ice.heat_to_change_phase),11                                                       ice.temperature_after => "0 °C"12   deduce_from "Specific heat of copper = 0.39 J g⁻¹ K⁻¹", copper.specific_heat_capacity => "0.39e3 J kg-1 K-1"13   deduce_from "heat of fusion of water = 335 J g⁻¹", ice.latent_heat => "335e3 J/kg"14 15 16 17 18   ice_melted = ice.mass19   answer ice_melted:, in: "kg", figures: 220 21   conclusion "The copper cools to 0 °C, giving up heat that melts ice at 0 °C; the maximum melt occurs when all the copper's heat is used."22 end
round 24
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