play phryzby with physics

Thrice the Escape Speed

solved GravitationalPotentialEnergy

Q. The escape speed of a projectile on the earth's surface is 11.2 km/sve,0,be=11.2km/s. A body is projected out with thrice this speedv0,b=3⋅ve,0,be. What is the speed of the body far away from the earthVg,1,be=0J/kg? Ignore the presence of the sun and other planets. Answer in km/s.

earthv₀→ ∞v = ?vₑ = 11200 m/sV₀V = 0 J/kg
Inputs
ve,0,be
11.2 km/s
Outputs
speedv1,b?

How it's solved

Solved with GravitationalPotentialEnergy

Given

  • ve,0,be=11.2km/s
  • Vg,1,be=0J/kg from “far away from the earth”
  • v0,b=3⋅ve,0,be from “thrice this speed”

Find v1,b.

Working
  1. ve,0,be=11.2km/s=11200m/s
  2. thrice this speedv0,b=3⋅ve,0,be
  3. v0,b=3⋅11200
  4. v0,b=33600m/s
  5. escape speed from where it is(body, earth, away, 1)ve,0,be2=-2⋅Vg,0,be
  6. 112002=-2⋅Vg,0,be
  7. Vg,0,be=−6.272×107J/kg
  8. energy kept in free flight(body, earth, away)v1,b22+Vg,1,be=v0,b22+Vg,0,be
  9. v1,b22+0=3360022+(−6.272×107)
  10. v1,b=31.68km/s
  11. v1,b=31678.3838m/s=31.6783838km/s
  12. v1,b≈31.7km/sto 3 significant figures
Conclusion

Escaping uses up exactly the kinetic energy the escape speed carries, and what is left over is kept far away, so the squares of the speeds subtract.

The web of concepts

given read from the words equation asked

The Ruby that solves it

The question and its solution are small Ruby files. The engine runs them.

question.rb
1require_relative "../physics"23question :thrice_the_escape_speed do4  kind :numerical5  describes "The escape speed of a projectile on the earth's surface is %{escape}. A body is projected out with " \6            "thrice this speed. %{speed}? Ignore the presence of the sun and other planets. Answer in km/s."7  given escape: "11.2 km/s"8  asks speed: "What is the speed of the body far away from the earth"9end
solution.rb
1require_relative "../questions/thrice_the_escape_speed"2require_relative "../science/gravitation/gravitational_potential_energy"34solve :thrice_the_escape_speed, using: GravitationalPotentialEnergy do5  objects :body, :earth6  body.goes(:away)78  take escape: body.escape_speed(from: earth, at: away.start)910  deduce_from "thrice this speed", body.initial_speed => 3 * body.escape_speed(from: earth, at: away.start)11  deduce_from "far away from the earth", body.gravitational_potential(from: earth, at: away.end) => "0 J/kg"1213  speed = body.final_speed14  answer speed:, in: "km/s", figures: 31516  conclusion "Escaping uses up exactly the kinetic energy the escape speed carries, and what is left over is " \17             "kept far away, so the squares of the speeds subtract."18end
playground.rb
1require_relative "../solutions/thrice_the_escape_speed"23play_with :thrice_the_escape_speed do4  title "Thrice the Escape Speed"5end
The laws it drew on
quantitywrittenunitswithinfrom
gravitational constantGN m² kg⁻²—UniversalGravitation
massmkg0 … ∞UniversalGravitation
radius of the bodyRm0 … ∞UniversalGravitation
surface gravitygsm/s²—UniversalGravitation
separationrgm0 … ∞UniversalGravitation
gravitational intensityEgm/s²—UniversalGravitation
distance from the centrerm—GravitationalPotentialEnergy
height above the surfacehm—GravitationalPotentialEnergy
gravitational potentialVgJ/kg—GravitationalPotentialEnergy
escape speedvem/s—GravitationalPotentialEnergy
speedvm/s0 … ∞GravitationalPotentialEnergy
surface gravity of groundgs,gm/s²—
mass of groundmgkg0 … ∞
radius of the body of groundRgm0 … ∞
surface gravity of bodygs,bm/s²—
mass of bodymbkg0 … ∞
radius of the body of bodyRbm0 … ∞
surface gravity of earthgs,em/s²—
mass of earthmekg0 … ∞
radius of the body of earthRem0 … ∞
gravitational intensity of ground by bodyEg,gbm/s²—
separation of ground from bodyrg,gbm0 … ∞
gravitational intensity of ground by earthEg,gem/s²—
separation of ground from earthrg,gem0 … ∞
gravitational intensity of body by groundEg,bgm/s²—
separation of body from groundrg,bm0 … ∞
gravitational intensity of body by earthEg,bem/s²—
separation of body from earthrg,bem0 … ∞
gravitational intensity of earth by groundEg,egm/s²—
separation of earth from groundrg,em0 … ∞
gravitational intensity of earth by bodyEg,ebm/s²—
separation of earth from bodyrg,ebm0 … ∞
height above the surface of body from ground at start of awayh0,bm—
distance from the centre of body from ground at start of awayr0,bm—
height above the surface of body from ground at end of awayh1,bm—
distance from the centre of body from ground at end of awayr1,bm—
height above the surface of body from earth at start of awayh0,bem—
distance from the centre of body from earth at start of awayr0,bem—
height above the surface of body from earth at end of awayh1,bem—
distance from the centre of body from earth at end of awayr1,bem—
gravitational potential of body from ground at start of awayVg,0,bJ/kg—
gravitational potential of body from ground at end of awayVg,1,bJ/kg—
gravitational potential of body from earth at start of awayVg,0,beJ/kg—
gravitational potential of body from earth at end of awayVg,1,beJ/kg—
escape speed of body from ground at start of awayve,0,bm/s—
escape speed of body from ground at end of awayve,1,bm/s—
escape speed of body from earth at start of awayve,0,bem/s—
escape speed of body from earth at end of awayve,1,bem/s—
speed of body at end of awayv1,bm/s0 … ∞
speed of body at start of awayv0,bm/s0 … ∞
gs,b=G⋅mbRb2
gravity at the surface
Eg,oo=G⋅morg,oo2
law of gravitation
gs,g=G⋅mgRg2
gravity at the surface(ground)
gs,b=G⋅mbRb2
gravity at the surface(body)
gs,e=G⋅meRe2
gravity at the surface(earth)
Eg,gb=G⋅mbrg,gb2
law of gravitation(ground, body)
Eg,ge=G⋅merg,ge2
law of gravitation(ground, earth)
Eg,bg=G⋅mgrg,b2
law of gravitation(body, ground)
Eg,be=G⋅merg,be2
law of gravitation(body, earth)
Eg,eg=G⋅mgrg,e2
law of gravitation(earth, ground)
Eg,eb=G⋅mbrg,eb2
law of gravitation(earth, body)
h0,b=r0,b-Rg
height is measured from the surface(body, ground, away, 1)
h1,b=r1,b-Rg
height is measured from the surface(body, ground, away, 2)
h0,be=r0,be-Re
height is measured from the surface(body, earth, away, 1)
h1,be=r1,be-Re
height is measured from the surface(body, earth, away, 2)
Vg,0,b=−G⋅mgr0,b
potential of a mass(body, ground, away, 1)
Vg,1,b=−G⋅mgr1,b
potential of a mass(body, ground, away, 2)
Vg,0,be=−G⋅mer0,be
potential of a mass(body, earth, away, 1)
Vg,1,be=−G⋅mer1,be
potential of a mass(body, earth, away, 2)
ve,0,b2=-2⋅Vg,0,b
escape speed from where it is(body, ground, away, 1)
ve,1,b2=-2⋅Vg,1,b
escape speed from where it is(body, ground, away, 2)
ve,0,be2=-2⋅Vg,0,be
escape speed from where it is(body, earth, away, 1)
ve,1,be2=-2⋅Vg,1,be
escape speed from where it is(body, earth, away, 2)
v1,b22+Vg,1,b=v0,b22+Vg,0,b
energy kept in free flight(body, ground, away)
v1,b22+Vg,1,be=v0,b22+Vg,0,be
energy kept in free flight(body, earth, away)
v0,b=3⋅ve,0,be
thrice this speed