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A Solenoid with an Iron Core

solved Magnetisation

Q. A solenoid has a core of a material with relative permeability 400μr=400. The windings of the solenoid are insulated from the core and carry a current of 2 AI=2A. If the number of turns is 1000 m⁻¹n=1000m⁻¹, what is the magnetic field in the core, in teslas?

B = ?I = 2 An = 1000 turns/mμᵣ = 400HMI_m
Inputs
μr
400
I
2 A
n
1000 m⁻¹
Outputs
fieldB?

How it's solved

Solved with Magnetisation

Given

  • μr=400
  • I=2A
  • n=1000m⁻¹

Find B.

Working
  1. intensity of a solenoid(core)H=n⋅I
  2. H=1000⋅2
  3. H=2000A/m
  4. field in a magnetised core(core)B=μr⋅μ0⋅H
  5. B=400⋅1.25663706×10−6⋅2000
  6. B=1.005T
  7. B≈1.0Tto 2 significant figures
Conclusion

The windings alone set H; the core lines up its own atomic magnets along it, multiplying the field four hundred times over.

The web of concepts

given read from the words equation asked

The Ruby that solves it

The question and its solution are small Ruby files. The engine runs them.

question.rb
1require_relative "../physics"23question :a_solenoid_with_an_iron_core do4  kind :numerical5  describes "A solenoid has a core of a material with relative permeability %{permeability}. The windings of the " \6            "solenoid are insulated from the core and carry a current of %{current}. If the number of turns is " \7            "%{turns}, %{field}, in teslas?"8  given permeability: "400"9  given current: "2 A"10  given turns: "1000 m-1"11  asks field: "what is the magnetic field in the core"12end
solution.rb
1require_relative "../questions/a_solenoid_with_an_iron_core"2require_relative "../science/magnetism_and_matter/magnetisation"34solve :a_solenoid_with_an_iron_core, using: Magnetisation do5  objects :core67  take permeability: core.relative_permeability8  take current: core.current9  take turns: core.turns_per_length1011  field = core.magnetic_field12  answer field:, in: "T", figures: 21314  conclusion "The windings alone set H; the core lines up its own atomic magnets along it, multiplying the " \15             "field four hundred times over."16end
playground.rb
1require_relative "../solutions/a_solenoid_with_an_iron_core"23play_with :a_solenoid_with_an_iron_core do4  title "A Solenoid with an Iron Core"5end
The laws it drew on
quantitywrittenunitswithinfrom
permeability of free spaceμ0N/A²—Magnetisation
relative permeabilityμr——Magnetisation
currentIA—Magnetisation
turns per lengthnm⁻¹—Magnetisation
magnetic intensityHA/m—Magnetisation
magnetisationMA/m—Magnetisation
magnetic fieldBT—Magnetisation
magnetising currentImA—Magnetisation
magnetic intensity of groundHgA/m—
turns per length of groundngm⁻¹—
current of groundIgA—
magnetic intensity of coreHA/m—
turns per length of corenm⁻¹—
current of coreIA—
magnetisation of groundMgA/m—
relative permeability of groundμr,g——
magnetisation of coreMA/m—
relative permeability of coreμr——
magnetic field of groundBgT—
magnetic field of coreBT—
magnetising current of groundIm,gA—
magnetising current of coreImA—
Hc=nc⋅Ic
intensity of a solenoid
Mc=(μr,c-1)⋅Hc
magnetisation of a core
Bc=μr,c⋅μ0⋅Hc
field in a magnetised core
Bc=μ0⋅nc⋅(Ic+Im,c)
the current that would do without the core
Hg=ng⋅Ig
intensity of a solenoid(ground)
H=n⋅I
intensity of a solenoid(core)
Mg=(μr,g-1)⋅Hg
magnetisation of a core(ground)
M=(μr-1)⋅H
magnetisation of a core(core)
Bg=μr,g⋅μ0⋅Hg
field in a magnetised core(ground)
B=μr⋅μ0⋅H
field in a magnetised core(core)
Bg=μ0⋅ng⋅(Ig+Im,g)
the current that would do without the core(ground)
B=μ0⋅n⋅(I+Im)
the current that would do without the core(core)