play phryzby with physics

A Satellite Rocketed Free

solved EarthSatellites

Q. A satellite orbits the earth at a height of 400 kmho=400km above the surface. How much energy must be expended to rocket the satellite out of the earth's gravitational influence? Mass of the satellite = 200 kgm=200kg; mass of the earth = 6.0 × 10²⁴ kgMo=6.0×1024kg; radius of the earth = 6.4 × 10⁶ mRc,o=6.4×106m. Answer in joules.

M = 6×10²⁴ kgvrhrh = 400000 mR = 6.4×10⁶ mm = 200 kgE_b = ?k
Inputs
ho
400 km
m
200 kg
Mo
6e+24 kg
Rc,o
6400000.00 m
Outputs
energyEb?

How it's solved

Solved with EarthSatellites

Given

  • ho=400km
  • m=200kg
  • Mo=6.0×1024kg
  • Rc,o=6.4×106m

Find Eb.

Working
  1. ho=400km=400000m
  2. orbit radius from the centre(round)ro=Rc,o+ho
  3. ro=6.4×106+400000
  4. ro=6.8×106m
  5. binding energy of an orbit(round)Eb=G⋅Mo⋅m2⋅ro
  6. Eb=6.674×10−11⋅6×1024⋅2002⋅6.8×106
  7. Eb=5.889×109J
  8. Eb≈5.9×109Jto 2 significant figures
Conclusion

In orbit the satellite's kinetic energy makes up half of its negative potential energy, so it is still bound; freeing it takes the other half.

The web of concepts

given read from the words equation asked

The Ruby that solves it

The question and its solution are small Ruby files. The engine runs them.

question.rb
1require_relative "../physics"23question :a_satellite_rocketed_free do4  kind :numerical5  describes "A satellite orbits the earth at a height of %{height} above the surface. %{energy}? Mass of the " \6            "satellite = %{satellite}; mass of the earth = %{earth}; radius of the earth = %{radius}. Answer in " \7            "joules."8  given height: "400 km"9  given satellite: "200 kg"10  given earth: "6.0e24 kg"11  given radius: "6.4e6 m"12  asks energy: "How much energy must be expended to rocket the satellite out of the earth's gravitational influence"13end
solution.rb
1require_relative "../questions/a_satellite_rocketed_free"2require_relative "../science/gravitation/earth_satellites"34solve :a_satellite_rocketed_free, using: EarthSatellites do5  objects :satellite6  paths :orbit7  satellite.goes(:round, on: orbit)89  take height: orbit.height_of_the_orbit10  take satellite: satellite.mass11  take earth: orbit.central_mass12  take radius: orbit.central_radius1314  energy = satellite.binding_energy15  answer energy:, in: "J", figures: 21617  conclusion "In orbit the satellite's kinetic energy makes up half of its negative potential energy, so it is " \18             "still bound; freeing it takes the other half."19end
playground.rb
1require_relative "../solutions/a_satellite_rocketed_free"23play_with :a_satellite_rocketed_free do4  title "A Satellite Rocketed Free"5end
The laws it drew on
quantitywrittenunitswithinfrom
piπ—0 … ∞UniformCircularMotion
gravitational constantGN m² kg⁻²—UniversalGravitation
massmkg0 … ∞UniversalGravitation
radius of the bodyRm0 … ∞UniversalGravitation
surface gravitygsm/s²—UniversalGravitation
separationrgm0 … ∞UniversalGravitation
gravitational intensityEgm/s²—UniversalGravitation
positionxm—Velocity
displacementΔxm—Velocity
path lengthdm—Velocity
time takenΔts0 … 1e+05Velocity
average velocityvavm/s—Velocity
average speedcavm/s—Velocity
starting positionx0m—Velocity
final positionxm—Velocity
radiusrm0 … ∞UniformCircularMotion
speedvm/s0 … ∞UniformCircularMotion
angular speedωrad/s—UniformCircularMotion
revolutionsnrev——UniformCircularMotion
frequencyνHz0 … ∞UniformCircularMotion
centripetal accelerationacm/s²—UniformCircularMotion
against gravityq——UniformCircularMotion
periodTs0 … ∞UniformCircularMotion
gravitygm/s²—UniformCircularMotion
centripetal forceFcN—UniformCircularMotion
central massMkg—EarthSatellites
central radiusRcm—EarthSatellites
height of the orbithm—EarthSatellites
keplers constantkKs²/m³—EarthSatellites
binding energyEbJ—EarthSatellites
displacement of satellite during roundΔxm—
position of satellite at end of roundx1m—
position of satellite at start of roundx0m—
average velocity of satellite during roundvavm/s—
time taken of roundΔts0 … 1e+05
average speed of satellite during roundcavm/s—
path length of satellite during rounddm—
speed of satellite during roundvm/s0 … ∞
angular speed of satellite during roundωrad/s—
radius of orbitrom0 … ∞
period of roundTs0 … ∞
frequency of satellite during roundνHz0 … ∞
revolutions of satellite during roundnrev——
centripetal acceleration of satellite during roundacm/s²—
against gravity of satellite during roundq——
centripetal force on satellite during roundFcN—
mass of satellitemkg0 … ∞
central mass of orbitMokg—
keplers constant of orbitkK,os²/m³—
central radius of orbitRc,om—
height of the orbit of orbithom—
binding energy of satellite during roundEbJ—
surface gravity of groundgs,gm/s²—
mass of groundmgkg0 … ∞
radius of the body of groundRgm0 … ∞
surface gravity of satellitegsm/s²—
radius of the body of satelliteRm0 … ∞
gravitational intensity of ground by satelliteEg,gm/s²—
separation of ground from satelliterg,gm0 … ∞
gravitational intensity of satellite by groundEg,gm/s²—
separation of satellite from groundrgm0 … ∞
x0≡xi(start of motion)
starting position
x≡xi(end of motion)
final position
gs,b=G⋅mbRb2
gravity at the surface
Eg,oo=G⋅morg,oo2
law of gravitation
di(whole)=di(part 1)+di(part 2)
path in parts
Δtw=Δtp+Δtp
time in parts
Δx=x1-x0
change of position(round)
vav=ΔxΔt
displacement a time(round)
cav=dΔt
path a time(round)
v=ω⋅ro
speed round the circle(round)
ω=2⋅πT
once round a period(round)
ν=1T
rounds a second(round)
ν=nrevΔt
rounds over the time(round)
ac=v2ro
towards the centre(round)
q=acg
measured in gs(round)
Fc=m⋅ac
mass times the turning(round)
v2=G⋅Moro
held in orbit by gravity(round)
kK,o=4⋅π2G⋅Mo
keplers constant of an orbit(round)
T2=kK,o⋅ro3
law of periods(round)
ro=Rc,o+ho
orbit radius from the centre(round)
Eb=G⋅Mo⋅m2⋅ro
binding energy of an orbit(round)
gs,g=G⋅mgRg2
gravity at the surface(ground)
gs=G⋅mR2
gravity at the surface(satellite)
Eg,g=G⋅mrg,g2
law of gravitation(ground, satellite)
Eg,g=G⋅mgrg2
law of gravitation(satellite, ground)